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Next: example Up: Elastic collisions Previous: Center of mass reference

Back to the old frame

What did going to the center of mass velocity frame do for us? It told us the two balls reverse their velocties in that particular frame. But we want to know what happens in our original frame. Can we express what we just learned in a way that'll help us solve our original problem?

If we ask what happens to the difference in velocities before and after the collision, that'll tell us something independent of reference frame. The difference in the velocity of the two balls is always the same irrespective of frame. So what happens to the difference in velocities?

In the center of mass frame we see from eqn. 1.57 that tex2html_wrap_inline1421 . But as was just stated, this is true in our original frame

equation458

That is, the difference in velocities just reverse sign after the collision. You could also say that for any one dimensional elastic collision relative velocity of approach equals the relative velocity of recession. This is true in any reference frame. This equation is nice because it's linear. Its key to figuring out problems with elastic collisions.

So we now have two linear equations that we have to solve

eqnarray466

Multiply the second equation by tex2html_wrap_inline1069 , and add it to the first equation to eliminate tex2html_wrap_inline1393

equation477

Solving for tex2html_wrap_inline1395

  equation485

We can get tex2html_wrap_inline1393 most easily by interchanging the indices 1 and 2

  equation494

Let's do a couple of examples now.



Joshua Deutsch
Fri Jan 17 12:19:41 PST 1997